Answer:
Volume of gas is 24.7×10⁴ L
Explanation:
Given data:
Moles of neon gas = 1.1×10⁴ mol
Temperature of gas = standard = 273 K
Pressure of gas = standard = 1 atm
Volume of gas = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
1 atm × V = 1.1×10⁴ mol ×0.0821 atm.L/ mol.K × 273 K
V = 24.7×10⁴ atm.L / 1 atm
V = 24.7×10⁴ L
