Answer:
Step-by-step explanation:
1.
[tex](1,-3)=(x_1,y_1)\\\\y =2x+2\\\\m = 2[/tex]
Substitute values into point-slope form
[tex]y-y_1=m(x-x_1)\\\\y -3 =2(x-(-1))\\\\y-3=2(x+1)\\\\y-3=2x+2\\\\y=2x+2+3\\\\y=2x+5[/tex]
2.
[tex](18,2) =(x_1,y_1)\\\\3y-x=-12[/tex]
Arrange equation in slope-intercept form (y=mx+b)and derive slope
[tex]3y =x-12\\\\\frac{3y}{3} =\frac{1x}{3} -\frac{12}{3} \\\\y = \frac{1}{3} x -4\\\\m = \frac{1}{3}[/tex]
Substitute values into point-slope form
[tex]y-y_1=m(x-x_1)\\\\\\y-2=\frac{1}{3} (x-18)\\\\y-2=\frac{1}{3} x -6\\\\y=\frac{1}{3} x -6+2\\\\y=\frac{1}{3} x -4[/tex]
