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On an unknown planet, an astronaut drops an object from rest. She observes that the object falls a distance of 10 meters during a time interval of 2 seconds. What is the magnitude of the acceleration due to gravity on that planet?

Respuesta :

Answer:

The magnitude of the acceleration due to gravity is  [tex]5\ m/s^2[/tex]

Explanation:

Free Fall Motion

A free-falling object falls under the sole influence of gravity of the planet and do not encounter air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value depends on the planet where the motion occurs.

The distance traveled by a dropped object is:

[tex]\displaystyle y=\frac{gt^2}{2}[/tex]

Where t is the time taken to fall a distance y and g is the acceleration of gravity. If we know t and y, then we can calculate the value of g by solving the above equation for g:

[tex]\displaystyle g=\frac{2y}{t^2}[/tex]

The astronaut drops an object from rest and observes when t=2 seconds, y=10 m, thus:

[tex]\displaystyle g=\frac{2\cdot 10}{2^2}=\frac{20}{4}[/tex]

[tex]g=5\ m/s^2[/tex]

The magnitude of the acceleration due to gravity is  [tex]\mathbf{5\ m/s^2}[/tex]