Answer:
Normal speed = 711.11 km/h (Approx)
Step-by-step explanation:
Assume;
Normal speed = x
New speed = x - 25% of x = 0.75 x
Time taken = t
New time taken = t + 1.5 hour
Total distance
Computation:
Total distance = 3,200 km
Speed = Distance/Time
x = 3200 / t
t = 3200/x
so,
0.75 x = 3200 / (t+1.5)
0.75 x = 3200 / (3200/x+1.5)
0.75 x = 3200 / [(3200 + 1,5x)x]
x = 711.11 km/h
Normal speed = 711.11 km/h (Approx)
The regular speed or rate of the trip is 2111.1 km per hour.
Suppose that ; speed of plane is = S
Due to inclement weather the pilot slow down the plan rate by 25%
then new speed = S-25% of S = 0.75S
Time taken = t
New time taken = t+1.5 hours
Total distance covered = 3000 km
[tex]\rm{Speed = Distance/Time}[/tex]
Initial speed of the plane was,
[tex]S=\dfrac{3000}{t}[/tex]
Time t can be written as,
[tex]t=\dfrac{3000}{S}[/tex]
So, the new speed will be,
[tex]\begin{aligned}S' &= \dfrac{3000}{t+1.5} \\0.75S &= \dfrac{3000}{t+1.5} \end{aligned}[/tex]
So, the regular speed of the trip can be calculated as,
[tex]0.75S = \dfrac{3000}{t+1.5} \\0.75S = \dfrac{3000}{\dfrac{3000}{S}+1.5} \\0.75S = \dfrac{3000S}{3000+1.5S}\\0.75S(3000+1.5S)=3000S\\[/tex]
Solving further,
[tex]625S+1.125S^2=3000S\\1.125S-2375=0\\S=\dfrac{2375}{1.125}\\S=2111.1[/tex]
Therefore, the regular speed or rate of the trip is 2111.1 km per hour.
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https://brainly.com/question/23774048
