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The gas pressure in an aerosol can is 1.5 atm and 25 degrees celcius. Assuming that the gas obeys the ideal gas equation, what is the pressure when the can is heated to 450 degrees Celsius?

Respuesta :

quasarJose

Answer:

3.6atm

Explanation:

Given parameters:

Initial pressure = 1.5atm

Initial temperature  = 25°C = 25 + 273  = 298K

Final temperature  = 450°C = 450 + 273  = 723K

Unknown:

Final pressure  = ?

Solution:

To solve this problem, we use the combined gas law and we assume a constant volume. The expression to solve this is given below;

                     [tex]\frac{P_{1} }{T_{1} }[/tex]   = [tex]\frac{P_{2} }{T_{2} }[/tex]

P and T are temperature values

1 and 2 are initial and final states

 Insert the parameters and solve;

              [tex]\frac{1.5}{298}[/tex]   = [tex]\frac{P_{2} }{723}[/tex]  

               P₂   = 3.6atm

samueladesida43

The new pressure when the aerosol can is heated to 450°C is 3.64atm.

HOW TO CALCULATE NEW PRESSURE:

  • The new pressure can be calculated by using the formula below:

P1/T1 = P2/T2

Where;

  1. P1 = initial pressure (atm)
  2. T1 = initial temperature (K)
  3. P2 = final pressure (atm)
  4. T2 = final temperature (K)

  • According to this question, P1 = 1.5atm, T1 = 25°C + 273 = 298K, P2 = ?, T2 = 450°C + 273 = 723K

  • 1.5/298 = P2/723

  • 723 × 1.5 = 298 × P2

  • 1084.5 = 298P2

  • P2 = 1084.5 ÷ 298

  • P2 = 3.64atm

  • Therefore, the new pressure when the aerosol can is heated to 450°C is 3.64atm.

Learn more at: https://brainly.com/question/11244611?referrer=searchResults

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