According to the following reaction, how many grams of sulfur are formed when 37.4 g of water are formed?

2 H2S(g) + SO2(g) → 3 S(s) + 2H2O(l)

Question

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Respuesta :

Neetoo Neetoo · Answer 1 · 2020-11-02T14:53:04+01:00

Answer:

Mass = 100.8 g

Explanation:

Given data:

Mass of sulfur form = ?

Mass of water formed = 37.4 g

Solution:

Chemical equation:

2H₂S + SO₂ → 3S + 2H₂O

Number of moles of water:

Number of moles = mass/molar mass

Number of moles = 37.4 g/ 18 g/mol

Number of moles = 2.1 mol

Now we will compare the moles of water with sulfur.

H₂O : S

2 : 3

2.1 : 3/2×2.1 = 3.15 mol

Mass of sulfur:

Mass = number of moles × molar mass

Mass = 3.15 mol × 32 g/mol

Mass = 100.8 g