Answer:
For the outer dimensions: length = 35 inches, width = 25 inches, and height = 15 inches.
Step-by-step explanation:
For the interior;
volume = 6000 [tex]in^{3}[/tex]
length, l = 3h
width, w = 2h
height = h
But,
Volume of a cuboid = length x width x height
So that;
6000 = 3h x 2h x h
6000 = 6[tex]h^{3}[/tex]
Divide through by 6 to have;
1000 = [tex]h^{3}[/tex]
h = [tex]\sqrt[3]{1000}[/tex]
= 10
Thus, the height is 10 inches. Thus;
length, l = 3h = 3 x 10 = 30 inches
width, w = 2h = 2 x 10 = 20 inches
For the outer dimension, since the concrete sides and bottom would be 5 inches thick. Then its dimension are;
length, l = 30 + 5 = 35 inches
width, w = 20 + 5 = 25 inches
height = 10 + 5 = 15 inches
