Answer:
0.32 mmol/L
Explanation:
A chemist prepares a solution of aluminum sulfite by measuring out 16.1 μmol of aluminum sulfite into a 50 mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mmol/L of the chemist's aluminum sulfite solution. Round your answer to 2 significant digits.
Step 1: Convert aluminum sulfite from "μmol" to "mmol".
We will use the following conversion factors:
1 mol = 10³ mmol
1 mol = 10⁶ μmol
16.1 μmol × (1 mol / 10⁶ μmol) × (10³ mmol/1 mol) = 0.0161 mmol
Step 2: Convert the volume of solution from "mL" to "L"
We will use the conversion factor 1 L = 10³ mL.
50 mL × (1 L / 10³ mL) = 0.050 L
Step 3: Calculate the concentration of the solution in mmol/L
C = 0.0161 mmol / 0.050 L = 0.32 mmol/L
