Answer:
The correct solution will be "1 m/s". The further explanation is given below.
Explanation:
The given values are:
m₁ = 3.00 kg
m₂ = 6.00 kg
v₁i = 5.00 m/s
v₂i = 2.00 m/s
Now,
⇒ [tex]v_1f = \frac{(\frac{m_{1}-m_2}{m_1+m_2} ) v1i }{(\frac{2m_2}{m_1+m_2} ) v_2i}[/tex]
On substituting the values, we get
⇒ [tex]=(\frac{3-6}{3+6} )\times 5 + (\frac{2\times 6}{3+6} )\times 2[/tex]
⇒ [tex]= 1 \ m/s[/tex]
