Answer:
Step-by-step explanation:
This system can simply be solved by substitution
[tex]3x + 2y = 14\\x = 4y - 2\\[/tex]
Now, replace x in the top equation by what it is defined by in the second equation
[tex]3(4y - 2) + 2y = 14\\12y - 6 + 2y = 14\\14y = 20\\y = \frac{20}{14} = \frac{10}{7}[/tex]
Now we can solve for x using the second equation
[tex]x = 4y-2\\x = 4(\frac{10}{7})-2\\x = \frac{40}{7} - \frac{14}{7} \\x = \frac{26}{7}[/tex]
[tex]x = \frac{26}{7}, y=\frac{10}{7} \\(\frac{26}{7},\frac{10}{7})[/tex]
