Answer:
[tex]the \: value \: of \: \boxed{x + y =8} [/tex]
Step-by-step explanation:
[tex]for \: the \: value \: of \: \boxed{x + y} \\ i \: will \: be \: using \: elimination \: method \to\\ 3x + y = 20 ........eq(1)\\ 2x - 2y = 8........eq(2) \\2 \times ...3x + y = 20 \\ 3 \times ...2x - 2y = 8 \\6x + 2y = 40 \\ 6x - 6y = 24 \\ 6x - 6x + 2y - ( - 6y) = 40 - 24 \\ 8y = 16 \\ y = 2 \\ .................. \\by \: substituiting \: y \: in \: the \: equation \: (1) \to \\ 3x + y = 20 \\ 3x + ( 2) = 20 \\ 3x +2 = 20 \\ 3x = 18 \\ x = 6 \\ ................ \\ hence \to \: x + y = 6 + 2 \\ = 8[/tex]
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