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Which inequality models this problem? the length of a rectangle is three times its width. if the perimeter is at most 112 centimeters, what is the greatest possible value for the width? a 2w 2⋅(3w)>112 b 2w 2⋅(3w)≤112 c 2w 2⋅(3w)≥112 d 2w 2⋅(3w)<112

Respuesta :

texaschic101
2W + 2L = P

P is at most 112.......< or = 112
L = 3W

answer is :
2W + 2(3W) < = 112 (thats less then or equal)


abidemiokin

The inequality that models this problem is 2(3w) * 2w  ≤112

Let the length of the rectangle be "l"

Let the width of the rectangle be "w"

The formula for calculating the perimeter of a rectangle is expressed as:

P = 2(l+w)

If the length of a rectangle is three times its width, this is expressed as:

l = 3w

If the perimeter is at most 112cm, hence;

P ≤112

2(l+w) ≤112

2(3w+w) ≤112

2(3w) * 2w  ≤112

Hence the inequality that models this problem is 2(3w) * 2w  ≤112

Learn more on inequalities here: https://brainly.com/question/15816805

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