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7. A spring balance reads force in Newton. The scale is 20 cm long and reads from 0 to
60 N. Find the potential energy of the spring when it read 40 N. ​

Respuesta :

Answer:

The potential  energy when it reads 40 N is [tex]PE = 5.33 \ J[/tex]

Explanation:

From the question we are told that

   The lowest reading of the spring balance is  0 N and this is at  0 cm = 0 m

   The height reading of the spring balance is 60 N  and this is at 20 cm =  0.20 m

   Generally the length corresponding to the reading of 40 N is mathematically represented as

       [tex]d = \frac{40 * 0.20 }{60 }[/tex]

=>    [tex]d = 0.133 \ m[/tex]

Generally the potential  energy is mathematically represented as

      [tex]PE = m * g * d[/tex]

Here

     [tex]F = mg = 40 N[/tex]

So  

     [tex]PE = 40 * 0.133[/tex]

=>  [tex]PE = 5.33 \ J[/tex]