Answer:
1. 3 s.
2. 33 m/s
Explanation:
From the question given above, we obtained the following data:
Height (h) = 56 m
1. Determination of the time taken for the person to get to the water.
Height (h) = 56 m
Acceleration due to gravity (g) = 9.8 m/s²
Time taken (t) =?
h = ½gt²
56 = ½ × 9.8 × t²
56 = 4.9 × t²
Divide both side by 4.9
t² = 56/4.9
Take the square root of both side
T = √(56/4.9)
T = 3.3 ≈ 3 s
Therefore, it will take the person approximately 3 s to get to the water.
2. Determination of the velocity with which the diver enters the water.
Initial velocity (u) = 0 m/s
Height (h) = 56 m
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) =?
v² = u² + 2gh
v² = 0² + (2 × 9.8 × 56)
v² = 0 + 1097.6
v² = 1097.6
Take the square root of both side
v = √(1097.6)
v = 33 m/s
Thus, the diver dives into the water with a velocity of 33 m/s.
