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A ball traveling 25 m/sec is struck by an implement (moving in the opposite direction) with enough force to accelerate 2 the ball at a rate of 130 m/sec . Calculate final velocity if the implement and the ball made contact for 0.5 sec.

Respuesta :

abidemiokin

Answer:

90m/s

Explanation:

Given

initial velocity of the ball u = 25m/s

acceleration a = 130m/s²

time t = 0.5secs

Required

Final velocity v

Using the equation of motion

v = u+at

Substitute the given values

v = 25 + 130(0.5)

v = 25 + 65

v = 90

Hence the final velocity if the implement and the ball made contact for 0.5 sec is 90m/s

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