Given :
Two vertical buildings 57 meters apart are 158 meters and 237 meters high.
To Find :
The angle of elevation from the top of the shorter building to the top of the taller building.
Solution :
Distance between height of building, h = 237 - 158 = 79 m.
Distance between these building , d = 57 m.
Now,
[tex]tan\ \theta = \dfrac{h}{d}\\\\tan\ \theta = \dfrac{79}{57}\\\\tan\ \theta = 1.386\\\\\theta = tan ^{-1} 1.386\\\\\theta = 54.19^{\circ}[/tex]
Therefore, the angle of elevation from the top of the shorter building to the top of the taller building is 54.19°.
Hence, this is the required solution.
