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A 0.040kg block of of copper at 95℃ is placed in 0.105kg of water at an unknown temperature. After equilibrium is reached, the final temperature is 24℃. What is the initial temperature of the water?

Respuesta :

Answer:

Explanation:

heat lost by block of copper

= mass x specific heat x fall in temperature

= .04 x 385 x ( 95 - 24 )

= 1093.4 J

Heat gained by water

= .105 x 4200 x ( 24 - T ) ;  Here T is initial temperature of water .

= 441 ( 24 - T )

heat lost = heat gained

1093.4 = 441 ( 24 - T )

24 - T = 2.48

T = 21.52 ℃

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