? Question
Drag each label to the correct location on the table.
Classify the systems of equations based on the number of solutions they have.
No Solution
One Solution
Multiple Solutions
x + 2y = 1
x+10y = 50
2y - X= 12
2x - y = 17
x - 4y = 7
4x+10y = 40
2x + 5y = 40
3x+6y=3
2x+10y = 90
2y - 2 10
|2y - 3x = 5

Respuesta :

No Solution:

4x+10y = 40

2x + 5y = 40

2x - 8y=17

x - 4y = 7

One Solution:

2y - X= 12

2y - 2x =10

x + 10y =50

2x + 10y =90

Infinitely Many Solutions:

x + 2y = 1

3x + 6y= 3

2y - 3x = 5

2/5y -3/5x =1

Explanation: You only had 11 equations listed. But I believe these are the ones you want. I took the test and got them right. Hope it helps

Answer:

The guy one above is correct

here's an explanation.

Explanation:

When we solve this system, we get a result similar to a = a (for example, 0 = 0). This statement is true for all values of the variables. So, this system has infinitely many solutions.

When we solve this system, we get a result similar to a = b (for example, 0 = 3). This statement is false for all values of the variables. So, this system has no solution.

When we solve this system, we get a single solution at (40,1).

When we solve this system, we get a single solution at (2,7).

When we solve this system, we get a result similar to a = a (for example, 0 = 0). This statement is true for all values of the variables. So, this system has infinitely many solutions.

When we solve this system, we get a result similar to a = b (for example, 0 = 40). This statement is false for all values of the variables. So, this system has no solution.