Answer:
10.01461 kilojoules of thermal energy are absorbed when 98.5 g of water is heated from 24.5 ° C to 48.8 ° C
Explanation:
Sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change) causing a change in temperature.
The equation that allows to calculate heat exchanges in this case is:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the change in temperature.
In this case:
Replacing:
Q= 4.184 [tex]\frac{J}{g*C}[/tex] *98.5 g* 24.3 °C
Solving:
Q=10,014.61 J
Since 1 J is equal to 0.001 kJ, then you can apply the following rule of three: if 1 J is equal to 0.001 kJ, then 10,014.61 J is equal to how many kJ?
[tex]kJ=\frac{10,014.71 J*0.001 kJ}{1 J}[/tex]
kJ=10.01461 kJ
10.01461 kilojoules of thermal energy are absorbed when 98.5 g of water is heated from 24.5 ° C to 48.8 ° C
