The length of DF in the right triangle DEF is 10 units
The distance between two points A(x₁, y₁) and B(x₂, y₂) on the Cartesian plane is given by:
[tex]|AB|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Given that D is located at (0,8) and F is located at (6,0), hence:
[tex]Length\ of\ DF=\sqrt{(0-8)^2+(6-0)^2}=\sqrt{64 + 36} \\\\Length\ of\ DF=10[/tex]
Therefore the length of DF is 10 units
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