Respuesta :
Answer:
Conservation of momentum means that the final momentum must be the same as the initial momentum, where the momentum is defined as:
P = m*v
where m is mass, and v is velocity.
First, let's calculate Pi, the initial momentum.
Pi = Pi₁ + Pi₂
Where the subscripts 1 and 2 refer to each puck:
Pi₁ = 0.17kg*15m/s = 2.55 (kg*m/s)
Pi₂ = 0.11kg*0m/s = 0 (kg*m/s)
Pi = 2.55 (kg*m/s) + 0 (kg*m/s) = 2.55 (kg*m/s)
Now, after the collision we have that:
The first puck comes to rest, then:
Pf₁ = 0.17kg*0m/s = 0 (kg*m/s)
And the second puck will have a velocity v, that we want to find:
Pf₂ = 0.11kg*v
Pf = Pf₁ + Pf₂ = 0 (kg*m/s) + 0.11kg*v = 0.11kg*v
And by conservation of momentum we have:
Pi = Pf
2.55 (kg*m/s) = 0.11kg*v
We divide in both sides by 0.11kg
2.55 (kg*m/s)/0.11kg = v
23.2 m/s = v
And from this, the final momentum will be the same as the initial:
Pf = 23.2m/s*0.11kg = 2.55 (kg*m/s)
The total final momentum of the system is 2.55 Kg m/sec and this can be determined by conserving the momentum.
Given :
A hockey puck with a mass of 0.17 kg is traveling to the right along the ice at 15 m/s it strikes a second hockey puck with a mass of 0.11 kg the first hockey puck comes to rest after the collision of conservation of momentum holds.
The formula of the momentum is given below:
P = mv
Now, let conserve the moment, that is:
[tex]\rm P_i=P_f[/tex] --- (1)
where [tex]\rm P_i[/tex] is the initial momentum and [tex]\rm P_f[/tex] is the final momentum.
First, determine the initial momentum.
[tex]\rm P_i = 0.17\times 15 + 0.11\times 0= 2.55\;Kg\;m/sec[/tex]
Now, determine the final momentum.
[tex]\rm P_f = 0.17\times 0+ 0.11\times v = 0.11v\;Kg\;m/sec[/tex]
Now. substitute the value of [tex]\rm P_i[/tex] and [tex]\rm P_f[/tex] in the equation (1).
[tex]\rm 2.55=0.11v[/tex]
v = 23.18 m/sec
So, the final momentum can be calculated as:
[tex]\rm P = 23.18 \times 0.11[/tex]
P = 2.55 Kg m/sec
For more information, refer to the link given below:
https://brainly.com/question/4956182
