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The volume of carbon dioxide produced from 11.8 L ethane at STP is 22.4 L.
What is STP?
The STP can be given as the standard temperature and pressure. The standard temperature is 25° C and 1 atm.
It is known that, 22.4 L of gas at STP is equivalent to 1 mole.
Thereby, concentration of ethane is:
22.4 L = 1 mole
11.8 L = 1/22.4 * 11.8 moles
11.8 L = 0.5 moles
From the balanced chemical equation:
2 moles ethane produce = 4 moles carbon dioxide
0.5 moles ethane produce = 4/ 2* 0.5 moles carbon dioxide
0.5 moles ethane produce = 1 moles carbon dioxide
The volume of 1 mole of gas at STP is 22.4 L. Therefore, 11.8 L ethane produces 22.4 L carbon dioxide.
Learn more about STP, here:
https://brainly.com/question/26107741
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