Respuesta :
Answer:
Required Answer:-
Let
[tex]\qquad\quad {:}\longmapsto\sf The\: breadth =x\: ft[/tex]
[tex]\qquad\quad {:}\longmapsto\sf The\:length=x+1ft[/tex]
[tex]\qquad\quad {:}\longmapsto\sf Area=210ft^2 [/tex]
- As we know that in a rectangle
[tex]{\boxed {\sf Area=length\times Breadth}}[/tex]
- Substitute the values
[tex]\qquad\quad {:}\longmapsto\sf x (x+1)=210 [/tex]
[tex]\qquad\quad {:}\longmapsto\sf x^2+x=210 [/tex]
[tex]\qquad\quad {:}\longmapsto\sf x^2+x-210=0 [/tex]
- Factorise
[tex]\qquad\quad {:}\longmapsto\sf x^2+15x-14x-210=0 [/tex]
[tex]\qquad\quad {:}\longmapsto\sf x (x+15)-14 (x+15)=0 [/tex]
[tex]\qquad\quad {:}\longmapsto\sf (x+15)(x-14)=0 [/tex]
[tex]\qquad\quad {:}\longmapsto\sf x+15=0\:or\:x-14=0 [/tex]
[tex]\qquad\quad {:}\longmapsto\sf x=-15\:or\:x=14 [/tex]
- In menstruation there is no negative value .
- So (x=-15) can't be possible.
Hence correct value
[tex]\qquad\quad {:}\longmapsto\sf x=14[/tex]
__________________________
[tex]\qquad\quad {:}\longmapsto\sf Breadth =x=14ft[/tex]
[tex]\qquad\quad {:}\longmapsto\sf Length=x+1=14+1=15ft [/tex]
