Respuesta :
Answer:
The correct option is;
75 N
Explanation:
The given parameters are;
The angle of inclination of the ramp, θ = 42°
The gravitational force of the box = m × g = 112.1 N
Let [tex]F_f[/tex] represent the force of static friction acting on the box
Given that the box is at rest, we have
The component of the gravitational force acting along the inclined plane = The force of static friction acting on the box, [tex]F_f[/tex]
We have that the component of the gravitational force acting along the inclined plane = m × g × sin (θ) = [tex]F_f[/tex]
[tex]F_f[/tex] = m × g × sin (θ)
Substituting the values, gives;
[tex]F_f[/tex] = 112.1 × sin (42°) ≈ 75.0095409728
∴ The force of static friction acting on the box = [tex]F_f[/tex] ≈ 75 N
