Answer:
[tex]\sin \theta = \frac{40}{41}[/tex], [tex]\cos \theta = \frac{3}{82}[/tex], [tex]\tan \theta = \frac{80}{3}[/tex], [tex]\cot \theta = \frac{3}{80}[/tex], [tex]\sec \theta = \frac{82}{3}[/tex], [tex]\csc \theta = \frac{41}{40}[/tex]
Step-by-step explanation:
We notice that figure represents a right triangle, the hypotenuse has a length of 164 units and the leg opposite to [tex]\theta[/tex] has a length of 160 units. The sine of [tex]\theta[/tex] is:
[tex]\sin \theta = \frac{160}{164}[/tex]
[tex]\sin \theta = \frac{40}{41}[/tex]
The leg adjacent to [tex]\theta[/tex] is determine by the Pythagorean Theorem:
[tex]r = \sqrt{164^{2}-160^{2}}[/tex]
[tex]r = 6[/tex]
Then, the cosine of [tex]\theta[/tex] is:
[tex]\cos \theta = \frac{6}{164}[/tex]
[tex]\cos \theta = \frac{3}{82}[/tex]
Lastly, we determine the remaining trigonometric ratios by using these identities:
[tex]\tan \theta = \frac{\sin \theta}{\cos \theta}[/tex] (1)
[tex]\cot \theta = \frac{1}{\tan \theta}[/tex] (2)
[tex]\sec \theta = \frac{1}{\cos \theta}[/tex] (3)
[tex]\csc \theta = \frac{1}{\sin \theta}[/tex] (4)
If we know that [tex]\sin \theta = \frac{40}{41}[/tex] and [tex]\cos \theta = \frac{3}{82}[/tex], then the trigonometric ratios are, respectively:
[tex]\tan \theta = \frac{\frac{40}{41} }{\frac{3}{82} }[/tex]
[tex]\tan \theta = \frac{80}{3}[/tex]
[tex]\cot \theta = \frac{1}{\frac{80}{3} }[/tex]
[tex]\cot \theta = \frac{3}{80}[/tex]
[tex]\sec \theta = \frac{1}{\frac{3}{82} }[/tex]
[tex]\sec \theta = \frac{82}{3}[/tex]
[tex]\csc \theta = \frac{1}{\frac{40}{41} }[/tex]
[tex]\csc \theta = \frac{41}{40}[/tex]
