Answer:
Part A:
The other two ways we can rewrite F = m·a are;
1) F = dp/dt
2) F = m × d(v)/dt
Part B:
The mass of the wheelbarrow is 60 kg
Explanation:
Part A:
The other two ways of rewriting the equation are;
1) Force as the rate of change of momentum, F = dp/dt = d(m·v)/dt and
2) From the above equation, where, m is constant, we have;
F = d(m·v)/dt = m × d(v)/dt
∴ F = m × d(v)/dt
Part B:
The force with which we push the wheelbarrow = 240 N
The acceleration, a, given to the wheelbarrow (by the applied force) = 4 m/s²
From F = m × a
Where;
m = The mass of the wheelbarrow
m = F/a = 240 N/(4 m/s²) = 60 kg
The mass of the wheelbarrow = m = 60 kg.
