Answer:
The product will be less than the second factor.
Step-by-step explanation:
Given the expression
[tex]\frac{4}{5}\:\times \:1\frac{2}{5}\:=y[/tex]
solving to determine the product value
[tex]y=\:\frac{4}{5}\times \:\:1\frac{2}{5}[/tex]
[tex]=\frac{4}{5}\times \frac{7}{5}[/tex]
[tex]\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}[/tex]
[tex]=\frac{4\times \:7}{5\times \:5}[/tex]
[tex]=\frac{28}{5\times \:5}[/tex]
[tex]=\frac{28}{25}[/tex]
As the value of the second factor is:
[tex]1\frac{2}{5}=\frac{7}{5}=1.4[/tex]
And the product value is:
[tex]y=\frac{28}{25}=1.12[/tex]
It is clear that the product value 'y = 1.12' is lesser than the second factor value '1.4'.
i.e. 1.12 < 1.4
Thus, the product will be less than the second factor.
