Explanation:
The first wave was found to have a wavelength of 3 x 10⁵ m and the second wave had a wavelength of 3 x 10⁴ m
We need to find which wave have a higher frequency.
The relation between frequency and wavelength is given by :
[tex]c=f\lambda[/tex]
Let f₁ and f₂ be the frequency of wave 1 and wave 2.
[tex]f_1=\dfrac{c}{\lambda_1}\\\\f_1=\dfrac{3\times 10^8}{3\times 10^5}\\\\=1000\ Hz[/tex]
And
[tex]f_2=\dfrac{c}{\lambda_2}\\\\f_2=\dfrac{3\times 10^8}{3\times 10^4}\\\\=10000\ Hz[/tex]
Hence, the wave having less wavelength will have higher frequency. The wave having wavelength 3 x 10⁴ m will have higher frequency.
