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consider polynomial function f f(x)=(x-1)^2(x+3)^3(x+1)
use the equation to complete each statement about this function
The zero located and x=1 has a multiplicity of __ and the zero located at x=-3 has a multiplicity of __. The graph of the function will touch, but not cross, the x-axis at the x-value of __.

Respuesta :

Answer:

x1=-3, x2=-1,x3=1

Step-by-step explanation:

not sure if this helps but it did for me

varshamittal029

The blanks will have values 2, 3,  and 1 respectively.

What is zero of a function?

Zero of a function is defined as the roots of the function for which the value of the function will be 0 at those points.

If p is the zero of the function f(x)=0 then f(p)=0.

We have,

f(x) = (x-1)² (x+3)³ (x+1)

Now,

The zero is located at x=1 and has a multiplicity of 2.

Because the number of times a given factor appears in the factored form of the equation of a polynomial is called the multiplicity.

So,

Now,

The zero is located at x = - 3 and has a multiplicity of 3.

And,

The graph of the function will touch, but not cross, the x - axis at the x - value of 1.

Learn more about zero and multiplicity here:

https://brainly.com/question/14059007

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