Answer:
The magnitude of the work performed by the mover is 1863 J.
Explanation:
The work can be found using the following equation:
[tex] W = F*d [/tex]
Where:
F: is the force
d: is the displacement = 8.1 m
First, we need to find the net force in the horizontal direction, as follows:
[tex] \Sigma F_{x} = ma = 0 [/tex]
a = 0 since the mover slides a refrigerator at a constant velocity.
[tex] F_{x} = F_{f} = -230 N [/tex]
[tex]F_{f}[/tex]: is the friction force.
Then, the work is:
[tex] W = F*d = -230 N*8.1 m = -1863 J [/tex]
Therefore, the magnitude of the work performed by the mover is 1863 J.
I hope it helps you!
