Answer:
the real values that satisfy the equation are:
[tex]t=18,\:t=-18[/tex]
Step-by-step explanation:
Given the equation
$t² = 324$
Let us solve the equation
[tex]t^2=324[/tex]
[tex]\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]
[tex]t=\sqrt{324},\:t=-\sqrt{324}[/tex]
as
[tex]\sqrt{324}=18[/tex][tex]-\sqrt{324}=-18[/tex]
so
[tex]t=18,\:t=-18[/tex]
Thus, the real values that satisfy the equation are:
[tex]t=18,\:t=-18[/tex]
