Respuesta :

We are given:

Volume of Glucose solution = 144 mL  OR 0.144 L

Molarity of Glucose solution = 0.280 M

Number of moles of Glucose in the solution:

From the definition of Molarity, we know that:

Molarity = number of moles / volume(in L)

in this equation, multiplying both sides by Volume, we get:

number of moles = Molarity*Volume(in L)

replacing the variables

Number of moles = 0.280*(0.144L)

Number of moles = 0.04

Number of Molecules in the solution:

We know that:

Number of molecules = Number of Moles * Avogadro's number

Number of molecules = 0.04 * 6.022 * 10²³

Number of molecules = 0.24088 * 10²³

Number of molecules = 2.4088 * 10²²

Therefore, there are 2.4088 * 10²² molecules of Glucose in the given solution