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If in the reaction below 32 grams of C2H6 produces 44 grams of CO2, what is the % yield? 2C2H6 + 7O2 = 4CO2 + 6H2O
imagine the = is an arrow

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Answer: 46.875%

the moles of C2H6 is 32/(12.2+6) = 16/15 (mol)

the moles of CO2 is 44/(12 + 16.2) = 1 (mol)

have:

2C2H6 + 7O2 ⇒ 4CO2 + 6H2O

 0,5    <=                 1

=> C2H6 reacts 0.5 mol

=> H = [tex]\frac{0.5}{\frac{16}{15} }.100=46.875[/tex]%

Explanation:

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