Answer:
The time spent in air by the car is 2.19 s
The height of the cliff is 58.5 m
Explanation:
Given;
initial velocity of the car, u = 16 m/s
horizontal distance traveled, R = 35 m
The horizontal distance or range of a projectile is given as;
R = vt
where;
t is the time spent in air by the projectile
t = R/v
t = 35 / 16
t = 2.19 s
The height of the cliff is given as;
h = ut + ¹/₂gt²
h = (16 x 2.19) + ¹/₂(9.8)(2.19)²
h = 58.5 m
