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What force must be applied to the end of a rod along the x-axis of length 2.25 m in order to produce a torque on the rod about the origin of 11 z-hat N·m? Choose among the available options below. x,y,z,-z

Respuesta :

samuelonum1

Answer:

4.9N approx.

Explanation:

Step one:

given data

length of rod r= 2.25m

Required torque = 11 Nm

Required

The force needed to produce a torque of 11Nm

Step two:

"By definition, Torque is the twisting force that tends to cause rotation.

The point where the object rotates is known as the axis of rotation."

Mathematically,

[tex]\tau = rF\sin\theta[/tex]

[tex]\tau[/tex] = torque

r = radius

F = force

[tex]\theta[/tex] = angle between F and the lever arm

in this case is zero

[tex]\tau = rF\\\\F=\tau/r[/tex]

substituting we have

F=11/2.25

F=4.88N

F=4.9N approx.

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