Answer:
The molecular weight is [tex]Z = 111.2 \ g/mol[/tex]
Explanation:
From the question we are told that
The mass of the sample is [tex]m = 0.98 \ g[/tex]
The temperature is [tex]T = 348 K[/tex]
The volume which the gas occupied is [tex]V = 265 \ ml = 265 *10^{-3} L[/tex]
The pressure is [tex]P = 0.95 \ atm[/tex]
Generally from the ideal gas equation we have that
[tex]PV = n RT[/tex]
Here n is the number of moles of the gas while the R is the gas constant with value [tex]R = 0.0821 \ atm \cdot L \cdot mol^{-1} \cdot K^{-1}[/tex]
[tex]n = \frac{PV}{ RT}[/tex]
=> [tex]n = \frac{ 0.95 * 265 *10^{-3} }{ 0.0821 * 348}[/tex]
=> [tex]n = 0.00881 \ mol[/tex]
Generally the molecular weight is mathematically represented as
[tex]Z = \frac{m}{n}[/tex]
=> [tex]Z = \frac{0.98 }{0.00881}[/tex]
=> [tex]Z = 111.2 \ g/mol[/tex]
