Answer:
E = 8.26*10⁻¹⁰ N/C, due south.
Explanation:
- Assuming no other forces acting on the electron than the electrostatic force due to the electric field, we can apply Newton's 2nd law as follows:
[tex]F = -eE =ma (1)[/tex]
- Solving for E, we can find its magnitude as follows:
[tex]E =\frac{m*a}{e} = \frac{9.1e-31 kg*145m/s2}{1.6e-19C} = 8.26e-10 N/C (1)[/tex]
- The direction of the electric field is by definition the one that would take a positive test charge, so if the electron is accelerated to the north, the electric field would exactly oppose to this direction, so it is directed due south.
