Respuesta :

abidemiokin

Answer:

Tn = 2/3^(n-1)

Step-by-step explanation:

The nth term of a geometric progression is expressed as

Tn = ar^{n-1}

a is the first term

n is the number of terms

r is t common ratio

From the sequence

a = 2/9

r = (2/3)/(2/9) = 2/(2/3) =3

Substitute

Tn = 2/9(3)^(n-1)

Tn = 2/3^(n-1)

Hence the required equation is Tn = 2/3^(n-1)

catgoesmoomc

Answer:

the actual answer is [tex]a_{n}[/tex][tex]=(\frac{2}{9} )3^{n-1}[/tex]

test taken, I know the real numbers for the question, and the real answer, and this is it

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