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A trombone acts like an open pipe of length 2.96 m .On a cold day it plays,its 4th harmonic at 221 hz what is the speed of the sound waves in the horn that day?

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Answer:

327.08 m/s

Step-by-step explanation:

Given that:

Length of pipe = 2.96m

4th harmonic frequency = 221 Hz

Speed of wave in the horn :

Speed of wave (v) = fλ

For 4th harmonic :

Wavelength, λ = (2/4)L

λ = L/2 ; 2λ = L

2λ = 2.96

λ = 2.96 / 2

λ = 1.48 m

Hence, speed of wave in the horn = 221 * 1.48 = 327.08 m/s

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