Answer:
B. 6.6 m
Explanation:
Given;
speed of Jared , v = 7.1 m/s
time taken, T = 5.8 s
let the radius of the traffic circle = r
The speed of Jared is calculated as;
[tex]v = \frac{2\pi r}{T}[/tex]
Where;
v is speed of Jared
T is period of the motion
r is radius of the traffic circle
[tex]r = \frac{vT}{2\pi} \\\\r = \frac{7.1 \ \times \ 5.8}{2\pi} \\\\r = 6.55 \ m\\\\r = 6.6 \ m[/tex]
Therefore, the radius of the traffic circle is 6.6 m.
