Answer:
Mass of water == 1.71 g
Explanation:
Given data:
Initial temperature of water = 10°C
Final temperature of water = 50°C
Energy absorbed = 286 J
Mass of water = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water is 4.18 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 50°C - 10°C
ΔT = 40°C
by putting values,
286 J = m × 4.18 J/g.°C × 40°C
286 J = m × 167.2 J/g
m = 286 J / 167.2 J/g
m = 1.71 g
