F(x) = x^2 + 2x - 4
G(x) = 3x + 1
Find g(f(x))
- when it says g(f(x)), this means that you plug in the equation or value you were given for f(x) into EVERY x-value seen in the g(x) equation.
-in the g(x) equation (3x + 1) you were given ONE x-value.
So...
-you replace the x with the f(x) equation which is, x^2 + 2x - 4 (as shown below)
g(f(x)) = 3(x^2 + 2x - 4) + 1
• then distribute the 3 on the outside of the brackets with each number inside the bracket
= 3x^2 + 6x - 12 + 1
• add all the like terms up and you should get your final equation
= 3x^2 + 6x - 11 OR 3x^2 + 6x + (-11)
*Remember to always follow the BEDMAS or PEDMAS rule
I hope this helps. If you have any questions please let me know in the comment section.
