Answer:
[tex]T_2 = 77.5c[/tex]
Explanation:
From the question we are told that
Temp of first bolts[tex]T_1=100[/tex]
Temp of 2nd bolt [tex]T_2=55[/tex]
Generally the equation showing the relationship between heat & temperature is given by
[tex]q=cm \triangle T[/tex]
Generally heat released by the iron bolt = heat gained by the iron bolt
Generally solving mathematically
[tex]-(0.45*m* (T_2-100 \textdegree c)) = 0.45*m*(T_2 -55\textdegree c)[/tex]
[tex]-(T_2-100 \textdegree c)) = (T_2 -55 \textdegree c)[/tex]
[tex]T_2 +T_2= 100 \textdegree c+55 \textdegree c[/tex]
[tex]T_2=\frac{155 \textdegree c}{2}[/tex]
[tex]T_2 = 77.5 \textdegree c[/tex]
Therefore [tex]T_2 = 77.5 \textdegree c[/tex] is the final temperature inside the container
