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Put equal parts of each 12%+38%=50%
50% divided by 2= 25%

To make 100 ml of 25% saline solution, Riley will need 50 ml = 12% saline mixture and 50 ml= 38% saline mixture.

Given,

We have 12% and 38% of saline mixtures.

We need to find the amount in ml from each saline mixture which would give us 100 ml of 25%.

What are the methods to solve a system of linear equations?

There are a number of methods but the most and easiest used method is the substitution method and the elimination method.

We can make two linear equations from the given statements.

Let x = amount from 12% saline mixture and y = amount from 38% saline mixture.

Now we need to make 100 ml of 25% saline.

so,

x + y = 100.

So we have two equations.

x + y = 100..............(1)

12% of x + 38% of y = 100 x 25%

0.12x + 0.38 = 25 ...............(2)

Using the substitution method we have,

x = 100 - y

Putting x = 100 - y in {2}

0.12 ( 100 - y ) + 0.38y

= 2512 - 0.12y + 0.38y

= 250.38y - 0.12y

= 25 - 120.26y = 13y

= 13 / 0.26y = 50.

Putting y = 50 in (1)

x + y = 100x

100 -50x = 50.

So Riley will need 50 ml = 12% saline mixture and 50ml = 38% saline mixture to make 100 ml of 25% saline solution.

Learn more about finding proportion of mixtures here:

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