Answer:
93.33 g of Fe
Explanation:
The balanced equation for the reaction is given below:
4Fe + 3O₂ —> 2Fe₂O₃
Next, we shall determine the masses of Fe and O₂ that reacted from the balanced equation. This can be obtained as follow:
Molar mass of Fe = 56 g/mol
Mass of Fe from the balanced equation = 4 × 56 = 224 g
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mass of O₂ from the balanced equation = 3 × 32 = 96 g
SUMMARY:
From the balanced equation above,
224 g of Fe reacted with 96 g of O₂.
Finally, we shall determine the mass of Fe required to react with 40 g of O₂. This can be obtained as follow:
From the balanced equation above,
224 g of Fe reacted with 96 g of O₂.
Therefore, Xg of Fe will react with 40 g of O₂ i.e
Xg of Fe = (224 × 40)/96
Xg of Fe = 93.33 g
Therefore, 93.33 g of Fe is required to react with 40 g of O₂.
