Answer:
[tex] a = 6\sqrt 3,\:\:b =12,\:\:c=6\sqrt 2[/tex]
Step-by-step explanation:
[tex]by \: 30 \degree - 60 \degree - 90 \degree \: theorem \\ \\ 6 = \frac{1}{2} b\\ \\ 6 \times 2 = b \\ \\ 12 = b \\ \\ \huge\red {\boxed {b= 12}} \\ \\ a = \frac{ \sqrt{3} }{2} b \\ \\ a = \frac{ \sqrt{3} }{2} \times 12 \\ \\ \huge\purple {\boxed {a = 6 \sqrt{3}}} \\ \\ c = \frac{1}{ \sqrt{2} } b \\ \\ c = \frac{1}{ \sqrt{2} } \times 12 \\ \\ c = \frac{ \sqrt{2} }{2} \times 12 \\ \\ \huge\orange {\boxed {c = 6 \sqrt{2}}} \\ \\ [/tex]
