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A bag contains 2 red marbles, 3 green marbles, and 4 blue marbles.
If we choose a marble, then another marble without putting the first one back in the blag, what is the
probability that the first marble will be green and the second will be red?

Respuesta :

Answer:

number of green ÷ total number of marbles

times by

number of red ÷ total number of marbles left

so

(3/9) × (2/8) = (1/12)

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