Answer:
Height of the tree is 40.0 meters.
Step-by-step explanation:
From ΔABC,
m∠ABC = 90°
Since, m∠ABC = m∠CBD + m∠ABD
90° = 6° + m∠ABD
m∠ABD = 90°- 6° = 84°
By triangle sum theorem in ΔABD,
m∠ABD + m∠BDA + m∠DAB = 180°
84° + 29° + m∠BDA = 180°
m∠BDA = 180° - 113°
= 67°
By sine rule in ΔABD,
[tex]\frac{\text{sin}(\angle BDA)}{d}= \frac{\text{sin}(\angle ABD)}{h}[/tex]
[tex]\frac{\text{sin}(67)}{37}= \frac{\text{sin}(84)}{h}[/tex]
h = [tex]\frac{\text{sin}(84)\times 37}{\text{sin}(67)}[/tex]
h = 39.98
h ≈ 40.0 meters
Therefore, height of the tree is 40.0 meters.
The sine rule is the ratio of the side length to the sine of the opposite angles. Then the height of the tree is 40 meters.
Trigonometry deals with the relationship between the sides and angles of a triangle.
Because of prevailing winds, a tree grew so that it was leaning 6º from the vertical.
At a point d = 37 meters from the tree, the angle of elevation to the top of the trees is a = 29° (see figure).
∠ABC = 90
We have
In ΔABC
∠ABC = ∠CBD + ∠ABD
∠ABD = 90 - 6
∠ABD = 84
By triangle sum in ΔABD, we have
∠ABD + ∠BDA + ∠DAB = 180
∠BDA = 180 - 84 - 29
∠BDA = 67
Then by the sine rule, we have
[tex]\begin{aligned} \dfrac{\sin \angle BDA}{d} &= \dfrac{ \sin \angle ABD }{h}\\\\\dfrac{\sin 67}{37} &= \dfrac{\sin 84}{h}\\\\h &= \dfrac{\sin 84} \times 37{\sin 67}\\\\h &= 39.98 \approx 40 \end{aligned}[/tex]
More about the trigonometry link is given below.
https://brainly.com/question/22698523
