Explanation:
Answer:
Given :-
A closed cylindrical tank of radius 3.5 m and height 2 m is made from a sheet of metal.
To Find :-
How much sheet of metal is required.
Formula Used :-
[tex]{\red{\boxed{\large{\bold{T.S.A\: of\: cylinder\: =\: 2{\pi}r(r + h)}}}}}[/tex]
where,
r = Radius
h = Height
Solution :-
Given :
Radius = 3.5 m
Height = 2 m
According to the question by using the formula we get,
⇒ [tex]\sf T.S.A =\: 2 \times \dfrac{22}{7} \times 3.5(3.5 + 2)[/tex]
⇒ [tex]\sf T.S.A =\: 2 \times \dfrac{22}{7} \times 3.5(5.5)[/tex]
⇒ [tex]\sf T.S.A =\: 2 \times \dfrac{22}{7} \times 3.5 \times 5.5T.S.A=2×722×3.5×5.5
⇒ \sf T.S.A =\: 2 \times \dfrac{22}{7} \times 19.25[/tex]
⇒ [tex]\sf T.S.A =\: 2 \times 60.5[/tex]
➠ [tex]\sf\bold{\purple{T.S.A =\: 121\: {m}^{2}}}[/tex]
∴ 121 m² of sheet of metal is required.
