Answer:
[tex]T_f=20.03^{\circ} C[/tex]
Explanation:
Given that,
The specific heat capacity of iron is 450.5 J/g°C
The mass of block of iron, m = 15.5 kg
Initial temperature, [tex]T_i=20^{\circ} C[/tex]
Heat required, Q = 250 J
We need to find the final temperature of the iron. The formula for heat required is given by :
[tex]Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\\dfrac{Q}{mc}=(T_f-T_i)\\\\T_f=\dfrac{Q}{mc}+T_i\\\\T_f=\dfrac{250}{15.5(450.5)}+20\\\\T_f=20.03^{\circ} C[/tex]
So, the final temperature of the iron is [tex]20.03^{\circ} C[/tex].
